解密Golang数组Xtea ECB算法的字节数组
来源:stackoverflow
时间:2024-03-26 16:09:27 277浏览 收藏
**摘要** 本文解密一个使用XTEA-ECB算法加密的字节数组。它展示了如何使用“golang.org/x/crypto/xtea”库和一个自定义XTEA-ECB实现来解密该数组。
问题内容
我有一个输入字节数组:
60614e680e705d0fefcf7ac8102c4452 ecb0c85768f2f2dc52415c43a36712f0 31c9037dafd31f01ecb0c85768f2f2dc 7b00be7e5a15fee1e78c63c58c2c6861 fef9a1c4130a354c846448512e6a97ce 4a9005690d1e3808f065c957538e1bac 87e7228322ab39a6900146786840dc0b c536ad6afb6e4e3267fb045dd9c7e670 f1c2d2ac1fcc71ad06b7b194de4031f4 046744610aafa7b92fd3f392c3a5eeb1 474ffa60c0587e68ecb0c85768f2f2dc 2a88827461b41c99b2539b6bfdcd4325 be3ced59be7b594addb3366e076f6e47 0cc41df1eb3a8d93c99eb7bdad5a474c 33659653762910d0ecb0c85768f2f2dc ecb0c85768f2f2dc82e715e7952a79c4 660074ccc50741cab5eabb873ae706b4 c8b008128df0af80fece91741fc5f641 1145aab35ac9f6e0f8a937baed012d00 c3be705a5e8c3440ddc1cd4e0051cccc
对 xtea ecb 进行加密的算法。我尝试使用该库进行解密“golang.org/x/crypto/xtea”。
package main import ( "golang.org/x/crypto/xtea" "fmt" ) func main() { // encripte data test :=[]byte{ 0x60, 0x61, 0x4e, 0x68, 0x0e, 0x70, 0x5d, 0x0f, 0xef, 0xcf, 0x7a, 0xc8, 0x10, 0x2c, 0x44, 0x52, 0xec, 0xb0, 0xc8, 0x57, 0x68, 0xf2, 0xf2, 0xdc, 0x52, 0x41, 0x5c, 0x43, 0xa3, 0x67, 0x12, 0xf0, 0x31, 0xc9, 0x03, 0x7d, 0xaf, 0xd3, 0x1f, 0x01, 0xec, 0xb0, 0xc8, 0x57, 0x68, 0xf2, 0xf2, 0xdc, 0x7b, 0x00, 0xbe, 0x7e, 0x5a, 0x15, 0xfe, 0xe1, 0xe7, 0x8c, 0x63, 0xc5, 0x8c, 0x2c, 0x68, 0x61, 0xfe, 0xf9, 0xa1, 0xc4, 0x13, 0x0a, 0x35, 0x4c, 0x84, 0x64, 0x48, 0x51, 0x2e, 0x6a, 0x97, 0xce, 0x4a, 0x90, 0x05, 0x69, 0x0d, 0x1e, 0x38, 0x08, 0xf0, 0x65, 0xc9, 0x57, 0x53, 0x8e, 0x1b, 0xac, 0x87, 0xe7, 0x22, 0x83, 0x22, 0xab, 0x39, 0xa6, 0x90, 0x01, 0x46, 0x78, 0x68, 0x40, 0xdc, 0x0b, 0xc5, 0x36, 0xad, 0x6a, 0xfb, 0x6e, 0x4e, 0x32, 0x67, 0xfb, 0x04, 0x5d, 0xd9, 0xc7, 0xe6, 0x70, 0xf1, 0xc2, 0xd2, 0xac, 0x1f, 0xcc, 0x71, 0xad, 0x06, 0xb7, 0xb1, 0x94, 0xde, 0x40, 0x31, 0xf4, 0x04, 0x67, 0x44, 0x61, 0x0a, 0xaf, 0xa7, 0xb9, 0x2f, 0xd3, 0xf3, 0x92, 0xc3, 0xa5, 0xee, 0xb1, 0x47, 0x4f, 0xfa, 0x60, 0xc0, 0x58, 0x7e, 0x68, 0xec, 0xb0, 0xc8, 0x57, 0x68, 0xf2, 0xf2, 0xdc, 0x2a, 0x88, 0x82, 0x74, 0x61, 0xb4, 0x1c, 0x99, 0xb2, 0x53, 0x9b, 0x6b, 0xfd, 0xcd, 0x43, 0x25, 0xbe, 0x3c, 0xed, 0x59, 0xbe, 0x7b, 0x59, 0x4a, 0xdd, 0xb3, 0x36, 0x6e, 0x07, 0x6f, 0x6e, 0x47, 0x0c, 0xc4, 0x1d, 0xf1, 0xeb, 0x3a, 0x8d, 0x93, 0xc9, 0x9e, 0xb7, 0xbd, 0xad, 0x5a, 0x47, 0x4c, 0x33, 0x65, 0x96, 0x53, 0x76, 0x29, 0x10, 0xd0, 0xec, 0xb0, 0xc8, 0x57, 0x68, 0xf2, 0xf2, 0xdc, 0xec, 0xb0, 0xc8, 0x57, 0x68, 0xf2, 0xf2, 0xdc, 0x82, 0xe7, 0x15, 0xe7, 0x95, 0x2a, 0x79, 0xc4, 0x66, 0x00, 0x74, 0xcc, 0xc5, 0x07, 0x41, 0xca, 0xb5, 0xea, 0xbb, 0x87, 0x3a, 0xe7, 0x06, 0xb4, 0xc8, 0xb0, 0x08, 0x12, 0x8d, 0xf0, 0xaf, 0x80, 0xfe, 0xce, 0x91, 0x74, 0x1f, 0xc5, 0xf6, 0x41, 0x11, 0x45, 0xaa, 0xb3, 0x5a, 0xc9, 0xf6, 0xe0, 0xf8, 0xa9, 0x37, 0xba, 0xed, 0x01, 0x2d, 0x00, 0xc3, 0xbe, 0x70, 0x5a, 0x5e, 0x8c, 0x34, 0x40, 0xdd, 0xc1, 0xcd, 0x4e, 0x00, 0x51, 0xcc, 0xcc, } // key key := []byte("yuyuyuyuopopopop") c, _ := xtea.newcipher(key) myout := make([]byte, len(test)) // decrypte c.decrypt(myout, test) fmt.println(myout) }
我的结果与应有的结果不一致。也许我没有正确使用该库?或者数据类型有问题?我是 golang 新手。应输出的数组:
09300004100e00000104f47795590210 0000000000000000616161615d5d5d5d 09150000000000000000000000000000 000000000000000d1052545530322e30 312e3030303200000012040000000013 040000000014046161616115045d5d5d 5d1604010e00001704010e0000180401 0e00001904010e00001a04010e00001b 04010e00001c04010e00001d04010e00 001e01001f0100200100210100240100 25113235303032000000000000000000 0000002604ef1400002704930d00002d 01022e02e0012f05ffffffff00300103 3101003301003404050100003d20342e 3132382e323400000000000000000000 00000000000000000000000000004401 184f04960d0000500400000000570460 ea0000580422060000590460ea00005a 04e01500005b01005c01025d01005e01 005f010360010361010262010400011b
解决方案
也许有人会派上用场。由于不安全,库“golang.org/x/crypto/xtea”不包含 ecb 模型的 xtea 算法,因此我编写了自己的版本:
package main import ( "fmt" "encoding/hex" "encoding/binary" ) func main() { original := []byte{ 0x60, 0x61, 0x4e, 0x68, 0x0e, 0x70, 0x5d, 0x0f, 0xef, 0xcf, 0x7a, 0xc8, 0x10, 0x2c, 0x44, 0x52, 0xec, 0xb0, 0xc8, 0x57, 0x68, 0xf2, 0xf2, 0xdc, 0x52, 0x41, 0x5c, 0x43, 0xa3, 0x67, 0x12, 0xf0, 0x31, 0xc9, 0x03, 0x7d, 0xaf, 0xd3, 0x1f, 0x01, 0xec, 0xb0, 0xc8, 0x57, 0x68, 0xf2, 0xf2, 0xdc, 0x7b, 0x00, 0xbe, 0x7e, 0x5a, 0x15, 0xfe, 0xe1, 0xe7, 0x8c, 0x63, 0xc5, 0x8c, 0x2c, 0x68, 0x61, 0xfe, 0xf9, 0xa1, 0xc4, 0x13, 0x0a, 0x35, 0x4c, 0x84, 0x64, 0x48, 0x51, 0x2e, 0x6a, 0x97, 0xce, 0x4a, 0x90, 0x05, 0x69, 0x0d, 0x1e, 0x38, 0x08, 0xf0, 0x65, 0xc9, 0x57, 0x53, 0x8e, 0x1b, 0xac, 0x87, 0xe7, 0x22, 0x83, 0x22, 0xab, 0x39, 0xa6, 0x90, 0x01, 0x46, 0x78, 0x68, 0x40, 0xdc, 0x0b, 0xc5, 0x36, 0xad, 0x6a, 0xfb, 0x6e, 0x4e, 0x32, 0x67, 0xfb, 0x04, 0x5d, 0xd9, 0xc7, 0xe6, 0x70, 0xf1, 0xc2, 0xd2, 0xac, 0x1f, 0xcc, 0x71, 0xad, 0x06, 0xb7, 0xb1, 0x94, 0xde, 0x40, 0x31, 0xf4, 0x04, 0x67, 0x44, 0x61, 0x0a, 0xaf, 0xa7, 0xb9, 0x2f, 0xd3, 0xf3, 0x92, 0xc3, 0xa5, 0xee, 0xb1, 0x47, 0x4f, 0xfa, 0x60, 0xc0, 0x58, 0x7e, 0x68, 0xec, 0xb0, 0xc8, 0x57, 0x68, 0xf2, 0xf2, 0xdc, 0x2a, 0x88, 0x82, 0x74, 0x61, 0xb4, 0x1c, 0x99, 0xb2, 0x53, 0x9b, 0x6b, 0xfd, 0xcd, 0x43, 0x25, 0xbe, 0x3c, 0xed, 0x59, 0xbe, 0x7b, 0x59, 0x4a, 0xdd, 0xb3, 0x36, 0x6e, 0x07, 0x6f, 0x6e, 0x47, 0x0c, 0xc4, 0x1d, 0xf1, 0xeb, 0x3a, 0x8d, 0x93, 0xc9, 0x9e, 0xb7, 0xbd, 0xad, 0x5a, 0x47, 0x4c, 0x33, 0x65, 0x96, 0x53, 0x76, 0x29, 0x10, 0xd0, 0xec, 0xb0, 0xc8, 0x57, 0x68, 0xf2, 0xf2, 0xdc, 0xec, 0xb0, 0xc8, 0x57, 0x68, 0xf2, 0xf2, 0xdc, 0x82, 0xe7, 0x15, 0xe7, 0x95, 0x2a, 0x79, 0xc4, 0x66, 0x00, 0x74, 0xcc, 0xc5, 0x07, 0x41, 0xca, 0xb5, 0xea, 0xbb, 0x87, 0x3a, 0xe7, 0x06, 0xb4, 0xc8, 0xb0, 0x08, 0x12, 0x8d, 0xf0, 0xaf, 0x80, 0xfe, 0xce, 0x91, 0x74, 0x1f, 0xc5, 0xf6, 0x41, 0x11, 0x45, 0xaa, 0xb3, 0x5a, 0xc9, 0xf6, 0xe0, 0xf8, 0xa9, 0x37, 0xba, 0xed, 0x01, 0x2d, 0x00, 0xc3, 0xbe, 0x70, 0x5a, 0x5e, 0x8c, 0x34, 0x40, 0xdd, 0xc1, 0xcd, 0x4e, 0x00, 0x51, 0xcc, 0xcc} testKey := []byte("yuyuyuyuopopopop") block := make([]byte, 8) for i := 0; i< len(original)/8; i++ { block = decrypt(testKey , original[(i*8):((i+1)*8)], 32) fmt.Println(hex.Dump(block)) } } func decrypt(key []byte, block []byte, rounds uint32) ([]byte){ var k [4]uint32 var i uint32 end := make([]byte, 8) v0 := binary.LittleEndian.Uint32(block[:4]) v1 := binary.LittleEndian.Uint32(block[4:]) k[0] = binary.LittleEndian.Uint32(key[:4]) k[1] = binary.LittleEndian.Uint32(key[4:8]) k[2] = binary.LittleEndian.Uint32(key[8:12]) k[3] = binary.LittleEndian.Uint32(key[12:]) delta := binary.LittleEndian.Uint32([]byte{0xb9, 0x79, 0x37, 0x9e}) mask := binary.LittleEndian.Uint32([]byte{0xff, 0xff, 0xff, 0xff}) sum := (delta * rounds) & mask for i=0; i>5) + v0) ^ (sum + k[sum>>11 & 3]))) & mask sum = (sum - delta) & mask v0 = (v0 - (((v1<<4 ^ v1>>5) + v1) ^ (sum + k[sum & 3]))) & mask } binary.LittleEndian.PutUint32(end[:4], v0) binary.LittleEndian.PutUint32(end[4:], v1) return end }
本篇关于《解密Golang数组Xtea ECB算法的字节数组》的介绍就到此结束啦,但是学无止境,想要了解学习更多关于Golang的相关知识,请关注golang学习网公众号!
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