如何根据相同的值对数组进行分组
来源:stackoverflow
时间:2024-04-12 11:27:37 255浏览 收藏
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问题内容
我正在使用 golang,这是使用 struct 创建的 json 数据。但我们需要使用 rooms->code 基础值对数据进行分组。
在下面的 json 数据中,需要使用房间代码对数组进行分组。不要创建重复的 json 节点。 实际 json 数据
{
"responsestatus": "success",
"version": "v1.9",
"checkin": "2021-10-12",
"checkout": "2021-10-16",
"currency": "aed",
"hotels": [
{
"code": "ot000000001",
"name": "taj test hotel",
"rooms": [
{
"code": "9011",
"name": "beach villa with jacuzzi",
"rates": [
{
"subsupplierid": "dc",
"boardcode": "fb",
"rateplancode": "9011_0_11_136_136",
"channel": 23,
"allotment": 100,
"price": 1469.04,
"cancellationpolicy": {
"policies": null
}
}
]
},
{
"code": "8525",
"name": "doubello",
"rates": [
{
"subsupplierid": "dc",
"boardcode": "fb",
"rateplancode": "8525_0_11_136_136",
"channel": 23,
"allotment": 100,
"price": 4407.08,
"cancellationpolicy": {
"policies": null
}
}
]
},
{
"code": "8525",
"name": "doubello",
"rates": [
{
"subsupplierid": "dc",
"boardcode": "",
"rateplancode": "8525_0_22_136_136",
"channel": 23,
"allotment": 100,
"price": 7345.12,
"cancellationpolicy": {
"policies": null
}
}
]
}
]
}
],
"remark": ""
}
需要转换我的实际输出
{
"responseStatus": "SUCCESS",
"version": "v1.9",
"checkIn": "2021-10-12",
"checkOut": "2021-10-16",
"currency": "AED",
"hotels": [
{
"code": "OT000000001",
"name": "TAJ TEST HOTEL",
"rooms": [
{
"code": "9011",
"name": "Beach Villa With Jacuzzi",
"rates": [
{
"subSupplierId": "DC",
"boardCode": "FB",
"ratePlanCode": "9011_0_11_136_136",
"channel": 23,
"allotment": 100,
"price": 1469.04,
"cancellationPolicy": {
"policies": null
}
}
]
},
{
"code": "8525",
"name": "Doubello",
"rates": [
{
"subSupplierId": "DC",
"boardCode": "FB",
"ratePlanCode": "8525_0_11_136_136",
"channel": 23,
"allotment": 100,
"price": 4407.08,
"cancellationPolicy": {
"policies": null
}
}, {
"subSupplierId": "DC",
"boardCode": "",
"ratePlanCode": "8525_0_22_136_136",
"channel": 23,
"allotment": 100,
"price": 7345.12,
"cancellationPolicy": {
"policies": null
}
}
]
}
]
}
],
"remark": ""
}
需要对“code”:“8525”的数据进行分组
正确答案
您可以迭代 rooms 并将每个唯一的 room.code 存储在 map 中。当您遇到以前见过的 code 时,只需将其添加到 rates 数组中,这将是 map 中该键的值。然后,只需将新数字插入到现有数据结构中即可。
package main
import (
"encoding/json"
"fmt"
"io/ioutil"
"os"
)
type Response struct {
Status string `json:"responseStatus"`
Version string `json:"version"`
CheckIn string `json:"checkIn"`
CheckOut string `json:"checkOut"`
Currency string `json:"currency"`
Hotels []Hotel `json:"hotels"`
Remark string `json:"remark"`
}
type Hotel struct {
Code string `json:"code"`
Name string `json:"name"`
Rooms []Room `json:"rooms"`
}
type Room struct {
Code string `json:"code"`
Name string `json:"name"`
Rates []Rate `json:"rates"`
}
type Rate struct {
SupplierID string `json:"subSupplierId"`
BoardCode string `json:"boardCode"`
RateCode string `json:"ratePlanCode"`
Channel int `json:"channel"`
Allotment int `json:"allotment"`
Price float64 `json:"price"`
CancelPolicy Policy `json:"cancellationPolicy"`
}
type Policy struct {
Policies string `json:"policies"`
}
func main() {
byt, err := ioutil.ReadFile("foo.json")
if err != nil {
os.Exit(1)
}
resp := Response{}
json.Unmarshal(byt, &resp)
hotels := resp.Hotels
newHotels := make([]Hotel, 0)
for _, hotel := range hotels {
newRooms := make(map[string]Room)
for _, room := range hotel.Rooms {
if val, ok := newRooms[room.Code]; ok {
newRates := append(val.Rates, room.Rates...)
val.Rates = newRates
newRooms[room.Code] = val
} else {
newRooms[room.Code] = room
}
}
finalRooms := make([]Room, 0)
for _, v := range newRooms {
finalRooms = append(finalRooms, v)
}
hotel.Rooms = finalRooms
newHotels = append(newHotels, hotel)
}
resp.Hotels = newHotels
respJSON, err := json.MarshalIndent(resp, "", " ")
if err != nil {
os.Exit(1)
}
fmt.Printf(string(respJSON))
}
{
"responseStatus": "SUCCESS",
"version": "v1.9",
"checkIn": "2021-10-12",
"checkOut": "2021-10-16",
"currency": "AED",
"hotels": [
{
"code": "OT000000001",
"name": "TAJ TEST HOTEL",
"rooms": [
{
"code": "9011",
"name": "Beach Villa With Jacuzzi",
"rates": [
{
"subSupplierId": "DC",
"boardCode": "FB",
"ratePlanCode": "9011_0_11_136_136",
"channel": 23,
"allotment": 100,
"price": 1469.04,
"cancellationPolicy": {
"policies": ""
}
}
]
},
{
"code": "8525",
"name": "Doubello",
"rates": [
{
"subSupplierId": "DC",
"boardCode": "FB",
"ratePlanCode": "8525_0_11_136_136",
"channel": 23,
"allotment": 100,
"price": 4407.08,
"cancellationPolicy": {
"policies": ""
}
},
{
"subSupplierId": "DC",
"boardCode": "",
"ratePlanCode": "8525_0_22_136_136",
"channel": 23,
"allotment": 100,
"price": 7345.12,
"cancellationPolicy": {
"policies": ""
}
}
]
}
]
}
],
"remark": ""
}今天带大家了解了的相关知识,希望对你有所帮助;关于Golang的技术知识我们会一点点深入介绍,欢迎大家关注golang学习网公众号,一起学习编程~
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