如何根据相同的值对数组进行分组
来源:stackoverflow
时间:2024-04-12 11:27:37 255浏览 收藏
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问题内容
我正在使用 golang,这是使用 struct 创建的 json 数据。但我们需要使用 rooms->code 基础值对数据进行分组。
在下面的 json 数据中,需要使用房间代码对数组进行分组。不要创建重复的 json 节点。 实际 json 数据
{ "responsestatus": "success", "version": "v1.9", "checkin": "2021-10-12", "checkout": "2021-10-16", "currency": "aed", "hotels": [ { "code": "ot000000001", "name": "taj test hotel", "rooms": [ { "code": "9011", "name": "beach villa with jacuzzi", "rates": [ { "subsupplierid": "dc", "boardcode": "fb", "rateplancode": "9011_0_11_136_136", "channel": 23, "allotment": 100, "price": 1469.04, "cancellationpolicy": { "policies": null } } ] }, { "code": "8525", "name": "doubello", "rates": [ { "subsupplierid": "dc", "boardcode": "fb", "rateplancode": "8525_0_11_136_136", "channel": 23, "allotment": 100, "price": 4407.08, "cancellationpolicy": { "policies": null } } ] }, { "code": "8525", "name": "doubello", "rates": [ { "subsupplierid": "dc", "boardcode": "", "rateplancode": "8525_0_22_136_136", "channel": 23, "allotment": 100, "price": 7345.12, "cancellationpolicy": { "policies": null } } ] } ] } ], "remark": "" }
需要转换我的实际输出
{ "responseStatus": "SUCCESS", "version": "v1.9", "checkIn": "2021-10-12", "checkOut": "2021-10-16", "currency": "AED", "hotels": [ { "code": "OT000000001", "name": "TAJ TEST HOTEL", "rooms": [ { "code": "9011", "name": "Beach Villa With Jacuzzi", "rates": [ { "subSupplierId": "DC", "boardCode": "FB", "ratePlanCode": "9011_0_11_136_136", "channel": 23, "allotment": 100, "price": 1469.04, "cancellationPolicy": { "policies": null } } ] }, { "code": "8525", "name": "Doubello", "rates": [ { "subSupplierId": "DC", "boardCode": "FB", "ratePlanCode": "8525_0_11_136_136", "channel": 23, "allotment": 100, "price": 4407.08, "cancellationPolicy": { "policies": null } }, { "subSupplierId": "DC", "boardCode": "", "ratePlanCode": "8525_0_22_136_136", "channel": 23, "allotment": 100, "price": 7345.12, "cancellationPolicy": { "policies": null } } ] } ] } ], "remark": "" }
需要对“code”:“8525”的数据进行分组
正确答案
您可以迭代 rooms
并将每个唯一的 room.code
存储在 map
中。当您遇到以前见过的 code
时,只需将其添加到 rates
数组中,这将是 map
中该键的值。然后,只需将新数字插入到现有数据结构中即可。
package main import ( "encoding/json" "fmt" "io/ioutil" "os" ) type Response struct { Status string `json:"responseStatus"` Version string `json:"version"` CheckIn string `json:"checkIn"` CheckOut string `json:"checkOut"` Currency string `json:"currency"` Hotels []Hotel `json:"hotels"` Remark string `json:"remark"` } type Hotel struct { Code string `json:"code"` Name string `json:"name"` Rooms []Room `json:"rooms"` } type Room struct { Code string `json:"code"` Name string `json:"name"` Rates []Rate `json:"rates"` } type Rate struct { SupplierID string `json:"subSupplierId"` BoardCode string `json:"boardCode"` RateCode string `json:"ratePlanCode"` Channel int `json:"channel"` Allotment int `json:"allotment"` Price float64 `json:"price"` CancelPolicy Policy `json:"cancellationPolicy"` } type Policy struct { Policies string `json:"policies"` } func main() { byt, err := ioutil.ReadFile("foo.json") if err != nil { os.Exit(1) } resp := Response{} json.Unmarshal(byt, &resp) hotels := resp.Hotels newHotels := make([]Hotel, 0) for _, hotel := range hotels { newRooms := make(map[string]Room) for _, room := range hotel.Rooms { if val, ok := newRooms[room.Code]; ok { newRates := append(val.Rates, room.Rates...) val.Rates = newRates newRooms[room.Code] = val } else { newRooms[room.Code] = room } } finalRooms := make([]Room, 0) for _, v := range newRooms { finalRooms = append(finalRooms, v) } hotel.Rooms = finalRooms newHotels = append(newHotels, hotel) } resp.Hotels = newHotels respJSON, err := json.MarshalIndent(resp, "", " ") if err != nil { os.Exit(1) } fmt.Printf(string(respJSON)) } { "responseStatus": "SUCCESS", "version": "v1.9", "checkIn": "2021-10-12", "checkOut": "2021-10-16", "currency": "AED", "hotels": [ { "code": "OT000000001", "name": "TAJ TEST HOTEL", "rooms": [ { "code": "9011", "name": "Beach Villa With Jacuzzi", "rates": [ { "subSupplierId": "DC", "boardCode": "FB", "ratePlanCode": "9011_0_11_136_136", "channel": 23, "allotment": 100, "price": 1469.04, "cancellationPolicy": { "policies": "" } } ] }, { "code": "8525", "name": "Doubello", "rates": [ { "subSupplierId": "DC", "boardCode": "FB", "ratePlanCode": "8525_0_11_136_136", "channel": 23, "allotment": 100, "price": 4407.08, "cancellationPolicy": { "policies": "" } }, { "subSupplierId": "DC", "boardCode": "", "ratePlanCode": "8525_0_22_136_136", "channel": 23, "allotment": 100, "price": 7345.12, "cancellationPolicy": { "policies": "" } } ] } ] } ], "remark": "" }
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