如何省略外部 XML 元素的名称

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我需要生成这样的 xml 文件：

  <package>
    <dc:contributor id="creator1">john doe</dc:contributor>
    <meta refines="creator1" property="role" scheme="marc:relators">aut</meta>
    <meta refines="creator1" property="role" scheme="onix:codelist17">a01</meta>
    <meta refines="creator1" property="file-as">doe, john</meta>
    <meta refines="creator1" property="diplay-seq">1</meta>
    <dc:contributor id="reviewer1">mary poppins</dc:contributor>
    <meta refines="reviewer1" property="role" scheme="marc:relators">rev</meta>
    <meta refines="reviewer1" property="file-as">poppins, mary</meta>
    <meta refines="reviewer1" property="diplay-seq">1</meta>
    <dc:contributor id="translator1">alfred weasley</dc:contributor>
    <meta refines="translator1" property="role" scheme="marc:relators">trl</meta>
    <meta refines="translator1" property="role" scheme="onix:codelist17">b06</meta>
    <meta refines="translator1" property="file-as">weasley, alfred</meta>
    <meta refines="translator1" property="diplay-seq">1</meta>
  </package>

这里的顺序很重要。

我使用这种结构：

type pack struct {
    xmlname struct{}        `xml:"package"`
    people  []personwrapper `xml:""` // <-- is this the problem?
}

type person struct {
    id       string `xml:"id,attr"`
    name     string `xml:"-"`
    surname  string `xml:"-"`
    fullname string `xml:",innerxml"`
}

type meta struct {
    refines  string `xml:"refines,attr"`
    property string `xml:"property,attr"`
    scheme   string `xml:"scheme,attr,omitempty"`
    value    string `xml:",innerxml"`
}

type personwrapper struct {
    person person `xml:"dc:contributor"`
    metas  []meta `xml:"meta"`
}

有了这个我得到了：

<package>
  <People>
    <dc:contributor id="creator1">John Doe</dc:contributor>
    <meta refines="creator1" property="role" scheme="marc:relators">aut</meta>
    <meta refines="creator1" property="role" scheme="onix:codelist17">A01</meta>
    <meta refines="creator1" property="file-as">Doe, John</meta>
    <meta refines="creator1" property="diplay-seq">1</meta>
  </People>
  <People>
    <dc:contributor id="reviewer1">Mary Poppins</dc:contributor>
    <meta refines="reviewer1" property="role" scheme="marc:relators">rev</meta>
    <meta refines="reviewer1" property="file-as">Poppins, Mary</meta>
    <meta refines="reviewer1" property="diplay-seq">1</meta>
  </People>
  <People>
    <dc:contributor id="translator1">Ben Weasley</dc:contributor>
    <meta refines="translator1" property="role" scheme="marc:relators">trl</meta>
    <meta refines="translator1" property="role" scheme="onix:codelist17">B06</meta>
    <meta refines="translator1" property="file-as">Weasley, Ben</meta>
    <meta refines="translator1" property="diplay-seq">1</meta>
  </People>
</package>

如何去掉 外部标签？我尝试将内部结构包装到更高级别的其他结构中，但无法达到所需的结构。

解决方案

您可以为 personwrapper 实现 xml.Marshaler 接口（并将 xmlname 添加到嵌套结构中）。

type Pack struct {
    XMLName struct{} `xml:"package"`
    People  []PersonWrapper
}

type Person struct {
    XMLName  xml.Name `xml:"dc:contributor"`
    Id       string   `xml:"id,attr"`
    Name     string   `xml:"-"`
    Surname  string   `xml:"-"`
    FullName string   `xml:",innerxml"`
}

type Meta struct {
    XMLName  xml.Name `xml:"meta"`
    Refines  string   `xml:"refines,attr"`
    Property string   `xml:"property,attr"`
    Scheme   string   `xml:"scheme,attr,omitempty"`
    Value    string   `xml:",innerxml"`
}

type PersonWrapper struct {
    Person Person `xml:"dc:contributor"`
    Metas  []Meta `xml:"meta"`
}

func (pw PersonWrapper) MarshalXML(e *xml.Encoder, start xml.StartElement) error {
    if err := e.Encode(pw.Person); err != nil {
        return err
    }
    if err := e.Encode(pw.Metas); err != nil {
        return err
    }
    return nil
}

https://play.golang.org/p/hzrBdHXHwOB

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