登录
首页 >  Golang >  Go问答

golang模板json转yml格式

来源:stackoverflow

时间:2024-04-20 08:03:36 355浏览 收藏

IT行业相对于一般传统行业,发展更新速度更快,一旦停止了学习,很快就会被行业所淘汰。所以我们需要踏踏实实的不断学习,精进自己的技术,尤其是初学者。今天golang学习网给大家整理了《golang模板json转yml格式》,聊聊,我们一起来看看吧!

问题内容

您好,我希望使用传递到我们的 go api 的 json 数据创建以下格式的 yml。

zookeeper:
  configs:
  
    zookeeper_user: custom-user
    zookeeper_group: custom-group
      
    zookeeper_copy_files:
       - source_path: /path/to/file.txt
         destination_path: /tmp/file.txt

    zookeeper_some_otherfile:
       - source_path: /path/to/file.txt
         destination_path: /tmp/file.txt
  hosts:
    ip-172-31-34-246.us-east-2.compute.internal:
      zookeeper_id: 2
    ip-172-31-37-15.us-east-2.compute.internal:
      zookeeper_id: 3
    ip-172-31-34-231.us-east-2.compute.internal:
      zookeeper_id: 1


      # zookeeper:
      #   properties:
      #     initlimit: 6
      #     synclimit: 3
      # zookeeper_server:
      #   properties:
      #     num.io: 15
      # zookeeper_registry:
      #   properties:
      #     key: val
      # zookeeper_center:
      #   properties:
      #     key: val

使用以下结构来解组 json 数据

type service struct {
    name string `json:"name"`
    hosts []host `json:"hosts"`
    configs  map[string]interface{} `json:"configs"` 

}

type host struct {
    hostname         string                 `json:"host_name"`
    customhostconfig map[string]interface{} `json:"config"`
}
{{ range $s := $.services }}
{{ $s.name }}:
  {{ range $k,$v := $s.vars }}{{ $k }}: "{{ $v }}"
  {{ end }}
  hosts:
    {{ range $h := $s.hosts }}
    {{ $h.hostname }}: {{ range $k,$v := $h.customhostconfig }}
       {{ $k }}: "{{ $v }}"
      {{ end }}
{{ end }}{{ end }}

我正在使用上面的模板代码,它可以很好地创建以下代码

zookeeper:
  configs:

    zookeeper_user: custom-user
    zookeeper_group: custom-group


  hosts:
    ip-172-31-34-246.us-east-2.compute.internal:
      zookeeper_id: 2
    ip-172-31-37-15.us-east-2.compute.internal:
      zookeeper_id: 3
    ip-172-31-34-231.us-east-2.compute.internal:
      zookeeper_id: 1

我需要帮助,根据使用 configs map[string]interface{} json:"configs" 作为键值 json 的一部分传递的用户输入,以动态方式将以下配置部分添加到最终 yml 文件中`。具有正确的缩进级别。

zookeeper_copy_files:
       - source_path: /path/to/file.txt
         destination_path: /tmp/file.txt

    zookeeper_Some_otherfile:
       - source_path: /path/to/file.txt
         destination_path: /tmp/file.txt

      # zookeeper:
      #   properties:
      #     initLimit: 6
      #     syncLimit: 3
      # zookeeper_server:
      #   properties:
      #     num.io: 15
      # zookeeper_registry:
      #   properties:
      #     key: val
      # Zookeeper_center:
      #   properties:
      #     key: val

正确答案


不要使用 go 模板编写 yaml,只需使用 yaml 实现,例如:

package main

import (
    "fmt"

    "gopkg.in/yaml.v3"
)

type service struct {
    name    string                 `json:"name"`
    hosts   []host                 `json:"hosts"`
    configs map[string]interface{} `json:"configs"`
}

type host struct {
    hostname         string                 `json:"host_name"`
    customhostconfig map[string]interface{} `json:"config"`
}

var services []service

// create some sample data similar to what you show
func init() {
    var zk service
    zk.name = "zookeeper"
    zk.configs = map[string]interface{}{
        "zookeeper_user":  "custom-user",
        "zookeeper_group": "custom-group",
    }
    zk.hosts = []host{
        {"ip-172-31-34-246.us-east-2.compute.internal",
            map[string]interface{}{
                "zookeeper_id": 2,
            }},
        {"ip-172-31-37-15.us-east-2.compute.internal",
            map[string]interface{}{
                "zookeeper_id": 3,
            }},
    }
    services = []service{zk}
}

func main() {
    out := make(map[string]interface{})
    for _, service := range services {
        var hosts = make(map[string]interface{})
        for _, host := range service.hosts {
            hosts[host.hostname] = host.customhostconfig
        }
        out[service.name] = map[string]interface{}{
            "hosts":   hosts,
            "configs": service.configs,
        }
    }
    bytes, err := yaml.marshal(out)
    if err != nil {
        panic(err)
    }
    fmt.println(string(bytes))
}

输出(go playground):

zookeeper:
    configs:
        zookeeper_group: custom-group
        zookeeper_user: custom-user
    hosts:
        ip-172-31-34-246.us-east-2.compute.internal:
            zookeeper_id: 2
        ip-172-31-37-15.us-east-2.compute.internal:
            zookeeper_id: 3

这会立即解决深度嵌套数据的任何问题,因为 yaml 只是按原样转储结构。

今天关于《golang模板json转yml格式》的内容就介绍到这里了,是不是学起来一目了然!想要了解更多关于的内容请关注golang学习网公众号!

声明:本文转载于:stackoverflow 如有侵犯,请联系study_golang@163.com删除
相关阅读
更多>
最新阅读
更多>
课程推荐
更多>