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mysql中TIMESTAMPDIFF案例详解

来源:脚本之家

时间:2022-12-28 12:17:40 164浏览 收藏

本篇文章主要是结合我之前面试的各种经历和实战开发中遇到的问题解决经验整理的,希望这篇《mysql中TIMESTAMPDIFF案例详解》对你有很大帮助!欢迎收藏,分享给更多的需要的朋友学习~

1.  Syntax

TIMESTAMPDIFF(unit,begin,end); 根据单位返回时间差,对于传入的begin和end不需要相同的数据结构,可以存在一个为Date一个DateTime

2. Unit

支持的单位有

  • MICROSECOND
  • SECOND
  • MINUTE
  • HOUR
  • DAY
  • WEEK
  • MONTH
  • QUARTER
  • YEAR

3. Example

下面这个例子是对于TIMESTAMPDIFF最基本的用法,

  • 3.1 求 2017-01-01 - 2017-02-01 之间有几个月
SELECT TIMESTAMPDIFF(MONTH, '2017-01-01', '2017-02-01') as  result;

+--------+
| result |
+--------+
| 1 |
+--------+
1 row in set (0.00 sec)
  • 3.2 求 2017-01-01 - 2017-02-01 之间有几天
SELECT TIMESTAMPDIFF(DAY, '2017-01-01', '2017-02-01') as  result;

+--------+
| result |
+--------+
| 31 |
+--------+
1 row in set (0.00 sec)
  •  3.3 求 2017-01-01 08: 00:00 - 2017-01-01 08: 55:00 之间有几分钟
SELECT TIMESTAMPDIFF(MINUTE, '2017-01-01 08:00:00', '2017-01-01 08:55:00') result;

+--------+
| result |
+--------+
| 55 |
+--------+
1 row in set (0.00 sec)
  •  3.4 求 2017-01-01 08: 00:00 - 2017-01-01 08: 55:33 之间有几分钟
SELECT TIMESTAMPDIFF(MINUTE, '2017-01-01 08:00:00', '2017-01-01 08:55:33') result;

+--------+
| result |
+--------+
| 55 |
+--------+
1 row in set (0.00 sec)
  •  3.5 对于DAY, MINUTE进行计算DIFF时,会直接将相对应的DAY,MINUTE相减

  • 3.6 对于 SECOND 会怎样计算呢
SELECT TIMESTAMPDIFF(SECOND, '2017-01-01 08:00:00', '2017-01-01 08:55:33') result;

55 * 60 + 33 = 3333
+--------+
| result |
+--------+
|   3333 |
+--------+
1 row in set (0.00 sec)
  • 3.7 如何求数据库中两个date字段的diff
    • 3.7.1  建表
      CREATE TABLE demo (id INT AUTO_INCREMENT PRIMARY KEY, start_time DATE NOT NULL, end_time DATE NOT NULL);
      Query OK, 0 rows affected (0.10 sec)
    • 3.7.2  添加数据
      INSERT INTO demo(start_time, end_time)
      VALUES('1983-01-01', '1990-01-01'),
      ('1983-01-01', '1989-06-06'),
      ('1983-01-01', '1985-03-02'),
      ('1983-01-01', '1992-05-05'),
      ('1983-01-01 11:12:11', '1995-12-01');
    • 3.7.3 直接query数据
      select * from demo;
      +----+------------+------------+
      | id | start_time | end_time |
      +----+------------+------------+
      | 1 | 1983-01-01 | 1990-01-01 |
      | 2 | 1983-01-01 | 1989-06-06 |
      | 3 | 1983-01-01 | 1985-03-02 |
      | 4 | 1983-01-01 | 1992-05-05 |
      | 5 | 1983-01-01 | 1995-12-01 |
      +----+------------+------------+
      5 rows in set (0.00 sec)
    • 3.7.4 计算duration
      select *, TIMESTAMPDIFF(YEAR, start_time, end_time) as duration from demo;
      
      +----+------------+------------+----------+
      | id | start_time | end_time | duration |
      +----+------------+------------+----------+
      | 1 | 1983-01-01 | 1990-01-01 | 7 |
      | 2 | 1983-01-01 | 1989-06-06 | 6 |
      | 3 | 1983-01-01 | 1985-03-02 | 2 |
      | 4 | 1983-01-01 | 1992-05-05 | 9 |
      | 5 | 1983-01-01 | 1995-12-01 | 12 |
      +----+------------+------------+----------+
      5 rows in set (0.00 sec)
    • 3.7.5 其他应用
      select *, if(TIMESTAMPDIFF(YEAR, end_time, CURRENT_TIMESTAMP())= 26') as result from demo;
      
      +----+------------+------------+--------+
      | id | start_time | end_time | result |
      +----+------------+------------+--------+
      | 1 | 1983-01-01 | 1990-01-01 | >= 26 |
      | 2 | 1983-01-01 | 1989-06-06 | >= 26 |
      | 3 | 1983-01-01 | 1985-03-02 | >= 26 |
      | 4 | 1983-01-01 | 1992-05-05 | 
              
              

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