Golang sort.SliceStable 在排序后返回不一样的结果
来源:stackoverflow
时间:2024-02-16 20:15:24 160浏览 收藏
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问题内容
我使用sort.slicestable作为map[string]int,它从txt文件中读取,但排序后结果不同。我尝试过将映射转换为结构或切片,但是 ethier 磨损了,这通常是结果吗? 代码:
func teststableuseslice() { counts := make(map[string]int) f, err := os.open("/users/boroughfan/gitdocuments/golangpractise/ch01/dup/text_feel_the_light_lyrics.txt") if err != nil { fmt.fprintf(os.stderr, "dup:%v\n", err) } input := bufio.newscanner(f) for input.scan() { counts[input.text()]++ } f.close() /////////////////////////////////////////////////////////// linesslice := make([]string, 0, len(counts)) for line := range counts { linesslice = append(linesslice, line) } sort.slicestable(linesslice, func(i, j int) bool { return counts[linesslice[i]] < counts[linesslice[j]] }) for _, line := range linesslice { fmt.printf("%d\t%s\n", counts[line], line) } } func teststableusepair() { counts := make(map[string]int) f, err := os.open("/users/boroughfan/gitdocuments/golangpractise/ch01/dup/text_feel_the_light_lyrics.txt") if err != nil { fmt.fprintf(os.stderr, "dup:%v\n", err) } input := bufio.newscanner(f) for input.scan() { counts[input.text()]++ } f.close() /////////////////////////////////////////////////////////// pairlist := make([]pair, 0, len(counts)) for line := range counts { pairlist = append(pairlist, pair{line, counts[line]}) } sort.slicestable(pairlist, func(i, j int) bool { return pairlist[i].value < pairlist[j].value }) for _, pairs := range pairlist { fmt.printf("%d\t%s\n", pairs.value, pairs.key) } }
这是txt文件:
// this is the dup test file, contents are from the feel the light lyrics "Feel The Light" (from "Home" soundtrack) Hmm, hmm Hmm Here I go, here I go Feel better now, feel better now Here I go, here I go It's better now, feel better now Do you remember when we fell under Did you expect me to reason with thunder I still remember when time was frozen What seemed forever was just a moment Hurry up, hurry up There's no more waiting We're still worth saving Feel the light Shining in the dark of night Remember what we forgot I know it's a long shot But we're bringing it all back We're bringing it all back Feel the light Shining like the stars tonight Remember what we forgot I know it's a long shot But we're bringing it all back We're bringing it all back Here I go, here I go Feel better now, feel better now Here I go, here I go It's better now, feel better now I still remember when things were broken But put together the cracks we'll close in Hurry up, hurry up There's no more waiting We're still worth saving Feel the light Shining in the dark of night Remember what we forgot I know it's a long shot But we're bringing it all back We're bringing it all back Feel the light Shining like the stars tonight Remember what we forgot I know it's a long shot But we're bringing it all back We're bringing it all back You and I can have it all tonight So let's bring it back to life Now we have another chance to fly Another chance to make it right Feel the light Shining in the dark of night Remember what we forgot I know it's a long shot Feel the light Shining like the stars tonight Remember what we forgot I know it's a long shot But we're bringing it all back We're bringing it all back Here we go, here we go Feel better now, feel better now Here we go, here we go It's better now, feel better now
正确答案
for line := range counts { ...
将按照地图给出的随机顺序枚举存储在 counts
地图中的线。
sort.slicestable()
的“稳定”部分不会取消文本中出现次数相同的两行的随机化 - 恰恰相反:它将保留此类行的初始顺序。
例如:
“我们开始,我们开始”
和 “我们仍然值得保存”
都有计数 2,所以:
如果 “我们开始,我们开始”
出现在 “我们仍然值得保存”
之前(或之后)在您的初始切片中,它将保留在结果切片之前(或之后)调用 sort.slicestable()
后。
如果您想要一致的顺序,请选择一种对它们之间的行进行完全排序的方法:
sort.SliceStable(linesSlice, func(i, j int) bool { if counts[linesSlice[i]] != counts[linesSlice[j]] { return counts[linesSlice[i]] < counts[linesSlice[j]] } // in this example: if lines have same count, order them alphabetically: return linesSlice[i] < linesSlice[j] })
(请注意,如果元素之间的顺序完整,则不再需要 stable
)
文中关于的知识介绍,希望对你的学习有所帮助!若是受益匪浅,那就动动鼠标收藏这篇《Golang sort.SliceStable 在排序后返回不一样的结果》文章吧,也可关注golang学习网公众号了解相关技术文章。
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