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整合按键和对象的映射

来源:stackoverflow

时间:2024-02-19 10:15:23 129浏览 收藏

本篇文章主要是结合我之前面试的各种经历和实战开发中遇到的问题解决经验整理的,希望这篇《整合按键和对象的映射》对你有很大帮助!欢迎收藏,分享给更多的需要的朋友学习~

问题内容

我正在尝试从 go 中的两个地图创建对象地图。

第一张地图掌握着钥匙。第二个 map 具有以键作为值的对象。

基本上在这个例子中 - 有规则和这些规则的检测。最后 - 我想要一个以规则名称作为键的地图,以及附加到它们的检测地图(聚合它们)。

最后:我想要这样的东西(取自下面的 typescript 示例):

[log]: {
  "rule1": [
    {
      "name": "rule1",
      "message": "i found rule1"
    },
    {
      "name": "rule1",
      "message": "i found rule1 again"
    }
  ],
  "rule2": [
    {
      "name": "rule2",
      "message": "i found rule2"
    },
    {
      "name": "rule2",
      "message": "i found rule2 again"
    },
    {
      "name": "rule2",
      "message": "i found rule2 another time"
    }
  ]
}

为了展示这一点,我在 typescript 中创建了这个:

打字稿演示

当我尝试在 go 中做同样的事情时 - 我有点心理障碍,要做到这一点:

去演示

package main

import (
    "fmt"
)

type Rule struct {
    Name string `json:"name"`
}

type Detection struct {
    Name    string `json:"name"`
    Message string `json:"message"`
}

func main() {

    rules := []Rule{
        {
            Name: "rule1",
        },
        {
            Name: "rule2",
        },
    }

    detected := []Detection{
        {
            Name:    "rule1",
            Message: "I found rule1",
        },
        {
            Name:    "rule1",
            Message: "I found rule1 again",
        },
        {
            Name:    "rule2",
            Message: "I found rule2",
        },
        {
            Name:    "rule2",
            Message: "I found rule2 again",
        },
        {
            Name:    "rule2",
            Message: "I found rule2 another time",
        },
    }

    fmt.Println(rules)
    fmt.Println(detected)

    aggregatedDetections := map[string][]Detection{}

    for _, r := range rules {
        fmt.Printf("Assign %s to aggregatedDetections\n", r.Name)
    }

    fmt.Println(aggregatedDetections)

}

我知道,go 老手需要 < 1 分钟来完成此任务;)但是:尽管我认为我对 go 中的地图有基本的了解 - 我不知道这里会发生什么。特别是我如何在地图中分配空数组值,以便在下一步中填充它们。

我的问题终于是:如何获得所需的输出。


正确答案


您可以使用 if _,found := map[element]; 检查地图元素是否存在;找到 {},如果没有,则使用空切片创建它。然后您可以将元素添加到切片中。

查看代码:

package main

import (
    "fmt"
)

type Rule struct {
    Name string `json:"name"`
}

type Detection struct {
    Name    string `json:"name"`
    Message string `json:"message"`
}

func main() {

    rules := []Rule{
        {
            Name: "rule1",
        },
        {
            Name: "rule2",
        },
    }

    detected := []Detection{
        {
            Name:    "rule1",
            Message: "I found rule1",
        },
        {
            Name:    "rule1",
            Message: "I found rule1 again",
        },
        {
            Name:    "rule2",
            Message: "I found rule2",
        },
        {
            Name:    "rule2",
            Message: "I found rule2 again",
        },
        {
            Name:    "rule2",
            Message: "I found rule2 another time",
        },
    }

    fmt.Println(rules)
    fmt.Println(detected)

    aggregatedDetections := make(map[string][]Detection)

    for _, r := range rules {
        if _, found := aggregatedDetections[r.Name]; !found {
          aggregatedDetections[r.Name] = make([]Detection, 0)
        }
        msg := ""
        switch {
          case len(aggregatedDetections[r.Name]) == 0:
             msg = "I found " + r.Name
          case len(aggregatedDetections[r.Name]) == 1:
             msg = "I found " + r.Name+" again"
        default:             
             msg = "I found " + r.Name+" another time"
        }
        aggregatedDetections[r.Name] = append(aggregatedDetections[r.Name], Detection{
          Name: r.Name,
          Message: msg,
        })
        fmt.Printf("Assign %s to aggregatedDetections\n", r.Name)
    }

    fmt.Println(aggregatedDetections)

}

Playground

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